One message of an agent thread's history, as JAgentResult.messages lists them: its role - a Java enum - and its text, with the tool calls an assistant message asked for and the call a tool message answers.
for (JMessage m : result.messages()) {
switch (m.role()) {
case USER -> System.out.println("> " + m.content());
case ASSISTANT -> m.toolCalls().forEach(c -> System.out.println(c.name() + c.argumentsJson()));
case TOOL -> System.out.println(m.toolCallId().orElseThrow() + ": " + m.content());
case SYSTEM -> { }
}
}
A value: two are equal when every field is. toString prints the full text, as the Scala Message does. Not Serializable.
Value parameters
content
its text; empty, never null, for an assistant message with only tool calls (and for a message whose Scala text is null)
role
who wrote it
thinking
the reasoning text an ASSISTANT message's model reported; empty when there was none, and for the other roles
toolCallId
the id of the tool call a TOOL message answers; empty for the other roles (and for a TOOL message whose id is null)
toolCalls
the tool calls an ASSISTANT message asked for, in order; an empty list for the other roles. Unmodifiable.
It is reflexive: for any instance x of type Any, x.equals(x) should return true.
It is symmetric: for any instances x and y of type Any, x.equals(y) should return true if and only if y.equals(x) returns true.
It is transitive: for any instances x, y, and z of type Any if x.equals(y) returns true and y.equals(z) returns true, then x.equals(z) should return true.
If you override this method, you should verify that your implementation remains an equivalence relation. Additionally, when overriding this method it is usually necessary to override hashCode to ensure that objects which are "equal" (o1.equals(o2) returns true) hash to the same scala.Int. (o1.hashCode.equals(o2.hashCode)).
Value parameters
that
the object to compare against this object for equality.
Attributes
Returns
true if the receiver object is equivalent to the argument; false otherwise.
The default hashing algorithm is platform dependent.
Note that it is allowed for two objects to have identical hash codes (o1.hashCode.equals(o2.hashCode)) yet not be equal (o1.equals(o2) returns false). A degenerate implementation could always return 0. However, it is required that if two objects are equal (o1.equals(o2) returns true) that they have identical hash codes (o1.hashCode.equals(o2.hashCode)). Therefore, when overriding this method, be sure to verify that the behavior is consistent with the equals method.